(7x+1)(4x^2+35x-9)=0

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Solution for (7x+1)(4x^2+35x-9)=0 equation:


Simplifying
(7x + 1)(4x2 + 35x + -9) = 0

Reorder the terms:
(1 + 7x)(4x2 + 35x + -9) = 0

Reorder the terms:
(1 + 7x)(-9 + 35x + 4x2) = 0

Multiply (1 + 7x) * (-9 + 35x + 4x2)
(1(-9 + 35x + 4x2) + 7x * (-9 + 35x + 4x2)) = 0
((-9 * 1 + 35x * 1 + 4x2 * 1) + 7x * (-9 + 35x + 4x2)) = 0
((-9 + 35x + 4x2) + 7x * (-9 + 35x + 4x2)) = 0
(-9 + 35x + 4x2 + (-9 * 7x + 35x * 7x + 4x2 * 7x)) = 0
(-9 + 35x + 4x2 + (-63x + 245x2 + 28x3)) = 0

Reorder the terms:
(-9 + 35x + -63x + 4x2 + 245x2 + 28x3) = 0

Combine like terms: 35x + -63x = -28x
(-9 + -28x + 4x2 + 245x2 + 28x3) = 0

Combine like terms: 4x2 + 245x2 = 249x2
(-9 + -28x + 249x2 + 28x3) = 0

Solving
-9 + -28x + 249x2 + 28x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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